REXROTH R065802030 compact linear bushing

Name: R065802030 REXROTH
Brand: REXROTH
SKU: 29563-en-eur
Price: 62.12 EUR
Availability: InStock

KBC-20-NR

62.12 € ~~86.99 €~~ -28%

50+ pcs. with 1 to 3 days delivery to United States

Specifications

Low-cost Linear Bushing for general requirements
Small outer dimensions and highly compact construction
High dynamic load rating and long service life due to hardened segmental load-bearing plates with ball conformity in the track.
High travel speed (5 m/s)
Integrated wiper seals, external seals or no wiper seals

Seals	No seals
Radial clearance	Normal radial clearance (compact linear bushing)
Linear bushing version (NR)	Stainless steel

Series		Compact
Max. acceleration amax		150 m/s²
Length of linear bushing		30 mm
Permissible ambient temperature		-10 °C ... +80 °C
Footnote friction coefficient μ		Friction coefficients of unsealed Linear Bushings when lubricated with oil. The friction coefficient is lowest under heavy load, but can still be above the specified value even under a low load.
Footnote friction force FR		One wiper seal: Multiply by a factor of 0.5.
Footnote minimum dynamic load capacity Cmin		The dynamic load capacities are based on a total travel of 100,000 m. When based on 50,000 m, the C values in the table are to be multiplied by 1.26.
Footnote minimum static load capacity C0min		The load ratings are based on a total travel of 100, 00 m. When based on 50 000 m, the values in the table need to be multiplied by 1.26.

Maximum dynamic load capacity Cmax		990 N
Maximum permissible linear speed vmax		5 m/s
Outer diameter d		28 mm
Friction coefficient μ		0,001 ... 0,004
Footnote breakaway force		One wiper seal: Multiply by a factor of 0.5.
Footnote maximum dynamic load capacity Cmax		The dynamic load capacities are based on a total travel of 100,000 m. When based on 50,000 m, the C values in the table are to be multiplied by 1.26.
Breakaway force		3 N
Footnote maximum static load capacity C0max		The load ratings are based on a total travel of 100, 00 m. When based on 50 000 m, the values in the table need to be multiplied by 1.26.